Difference between revisions of "Canon talk:RPG Terminology"

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(LWQW)
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: Not really. The multiplier could be 5, 10, or even 100, but it's still level * multiplier, where a wizard progresses at 2 ^ level.
 
: Not really. The multiplier could be 5, 10, or even 100, but it's still level * multiplier, where a wizard progresses at 2 ^ level.
 
: In short, linear does not mean to add +1 per level. Just that it's on a linear graph and is in a straight line--regardless of how steep it is. --[[User:Ghostwheel|Ghostwheel]] ([[User talk:Ghostwheel|talk]]) 01:48, 19 December 2012 (UTC)
 
: In short, linear does not mean to add +1 per level. Just that it's on a linear graph and is in a straight line--regardless of how steep it is. --[[User:Ghostwheel|Ghostwheel]] ([[User talk:Ghostwheel|talk]]) 01:48, 19 December 2012 (UTC)
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::Okay, so let's say that Fighters are linear because they start at a value of 1 and add +5 per level, yes? So a level 20 Warrior (value 96) now has to fight 96 level 1 Warriors (value 1*96), but only 16 level 2 Warriors (value 6*16), which they can certainly also slaughter.
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::To generalize, if a Warrior's power is the function Power(Level) = m*Level+b, where b >= -m and m >= 0 because level 1 characters aren't worth less than nothing and level 2 characters are stronger than level 1 characters, the number of level 2 characters a level 20 Warrior would have to face cannot be greater than 20 (m=arbitrarily high value, b=negative that) or less than 1 (m=0).
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::And 2 ^ level is exponential, not quadratic.
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::I'd guess that the most accurate description would probably be Quadratic Warriors, Exponential Wizards, where the base of the exponent for Wizards is a tiny bit higher than 2. --[[User:Foxwarrior|Foxwarrior]] ([[User talk:Foxwarrior|talk]]) 02:07, 19 December 2012 (UTC)

Revision as of 02:07, 19 December 2012

LWQW

The problem with Linear Warriors, Quadratic Wizards is that it's wrong: a level 20 Warrior can slaughter 20 level 1 Warriors without breaking a sweat. The balance WotC declared that it was going for is exponential, which is what we call High balance, I believe. --Foxwarrior (talk) 01:42, 19 December 2012 (UTC)

Not really. The multiplier could be 5, 10, or even 100, but it's still level * multiplier, where a wizard progresses at 2 ^ level.
In short, linear does not mean to add +1 per level. Just that it's on a linear graph and is in a straight line--regardless of how steep it is. --Ghostwheel (talk) 01:48, 19 December 2012 (UTC)
Okay, so let's say that Fighters are linear because they start at a value of 1 and add +5 per level, yes? So a level 20 Warrior (value 96) now has to fight 96 level 1 Warriors (value 1*96), but only 16 level 2 Warriors (value 6*16), which they can certainly also slaughter.
To generalize, if a Warrior's power is the function Power(Level) = m*Level+b, where b >= -m and m >= 0 because level 1 characters aren't worth less than nothing and level 2 characters are stronger than level 1 characters, the number of level 2 characters a level 20 Warrior would have to face cannot be greater than 20 (m=arbitrarily high value, b=negative that) or less than 1 (m=0).
And 2 ^ level is exponential, not quadratic.
I'd guess that the most accurate description would probably be Quadratic Warriors, Exponential Wizards, where the base of the exponent for Wizards is a tiny bit higher than 2. --Foxwarrior (talk) 02:07, 19 December 2012 (UTC)